SVP aidez moi ! Factoriser : A=ab-ax-xb+x² B=x²y-y+x²-1 C=x²-x+1/4-(2x-1) D=x³+x²+x+1 E=x³-x²+x-1 F=x⁵+x⁴+x³+x²+x+1 G=x⁵-x⁴+x³-x²+x-1 H=(3x+1)²-x²-x-1/4

Réponse :

bonjour

Explications étape par étape

A=ab-ax+xb+x²

(ab-ax)-(xb-x²)

a(b-x)-x(b-x)

(b-x)(a-x)

x²y-y+x²-1

y(x²-1)+(x²-1)

(x²-1)(y+1)

x²-x+1/4-(2x-1)

x²-x+1/4=(x-1/2)²

(x-1/2)²-2(x-1/2)

(x-1/2)((x-1/2)-2)

(x-1/2)(x-5/2)

x³+x²+x+1

x²(x+1)+(x+1)

(x+1)(x²+1)

x³-x²+x-1

x²(x-1)+(x-1)

(x-1)(x²+1)

x^5+x^4+x^3+x²+x+1

x^4(x+1)+x²(x+1)+(x+1)

(x+1)( x^4+x²+1)

x^5-x^4+x^3-x²+x-1

x^4(x-1)+x²(x-1)+(x-1)

(x-1)(x^4+x²+1)

(3x+1)²-x²-x-1/4

(3x+1)²-(x²+x+1/4)

x²+x+1/4=(x+1/2)²

(3x+1)²-(x+1/2)²

(3x+1+x+1/2)(3x+1-x-1/2)

(4x+3/2)(2x+1/2)

Bonjour,

Factoriser :

A=ab-ax-xb+x²

A = (a - x) (b - x)

B=x²y-y+x²-1

B = (x - 1) (x + 1) (y - 1)

C=x²-x+1/4-(2x-1)

C = 1/4 (2x - 5) (2x - 1)

D=x³+x²+x+1

D = (x + 1) (x² + 1)

E=x³-x²+x-1

E = (x - 1) (x² + 1)

F=x⁵+x⁴+x³+x²+x+1

F = (x + 1) (x² - x + 1) (x² + x + 1)

G=x⁵-x⁴+x³-x²+x-1

G = (x - 1) (x² - x + 1) (x² + x + 1)

H=(3x+1)²-x²-x-1/4

H = 1/4 (4x + 1) (8x + 3).